Math, asked by yhcpikul, 1 year ago

if 8-i/3-2i=a+ib find a.

Answers

Answered by divya024
0
8-i(1/3-2)=a+ib =>8+i(2-1/3)=a+ib=>a=8
Answered by deb15
5
(8-i)(3+2i)/(3-2i)(3+2i)=a+ib
=>(24+16i-3i+2)/(9+4)=a+ib
=>(26+13i)/13=a+ib
=>2+i=a+ib
comparing both side
a=2,b=1
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