If 8 is divided into two parts such that the larger part
exceeds the square of the smaller part by 2, then the
half of the smaller number is
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your answer is 1
2 and 6 are the parts
Step-by-step explanation:
let the parts be x and y
x+y=8
x=8-y
x=y²+2
8-y=y²+2
y²+y-6=0
y²+3y-2y-6=0
y(y+3)-2(y+3)=0
y=2,y= -3
when y=2,x=6
when y= -3,x=11
part cannot be bigger so x=6,y=2
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