if (-8) is the zero of the polynomial f(x) = x²+ax-72 and g(x) = x²+10+b, find a and b also find the other zero of f(x)
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4
Answer:
P(x) =x^2 +10x+b
P(-8)=(-8)^2 +10*(-8)+b=0
64-80+b=0
-16+b=0
So, b=16
And, P(x)=x^2 +ax-72
P(-8)=(-8)^2 +a(-8)-72=0
64-8a-72=0
-8a=72-64
-8a=8
So, a=-1
Answered by
0
Answer:
a=-1,b=16 , the other zero = 2
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