If 8 kgs of potatoes and 7 kgs of carrots cost Rs.270 and 2kg of potatoes and 3 kgs of carrots cost Rs.120, what is the price of 1 kg each
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let one kg of potato be t and the other be v.
8t+7v=270 -eqn 1.
2t+3v=120 (xby 4)
8t+7v=270 -eqn 1
8t+12v=480 subtract
0t -5v = -210
5v=210
v=210/5=42.
Therefore, one kg of carrot costs Rs.42
t=120-42=78.
Therefore, one kg of potato costs Rs.78.
Hope this will help you.
8t+7v=270 -eqn 1.
2t+3v=120 (xby 4)
8t+7v=270 -eqn 1
8t+12v=480 subtract
0t -5v = -210
5v=210
v=210/5=42.
Therefore, one kg of carrot costs Rs.42
t=120-42=78.
Therefore, one kg of potato costs Rs.78.
Hope this will help you.
Revolution:
8t+7v=270...give the values..it is not possible
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