Math, asked by aryanskataria, 17 days ago

If 8^(m+3)/2^2=2^(4m), then what is the value of m?

Answers

Answered by sjagadish1996
1
Answer:m=7

Step-by-step explanation:
here 8^(m+3) can be written as 2^3(m+3)=2^(3m+9) and
2^(3m+9) /2^2= 2^(3m+9) ×2^(-2)
2^(3m+9-2)
2^(3m+7)
Then according to question 2^(3m+7)=2^4m
Then as we know bases are equal the powers should be equal the
3m-7=4m
Them m=7
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