Question

if 8 oranges cost 10.40 how many oranges can be bought for rupees 33.80?

Answer 1

we can solve this question in the form of direct variation
x1:y1::x2:y2
x is the number of oranges
y is the cost
8:10.40::x2:33.80
we know that product of extremes is equal to product of means
8*33.80=10.40x2
x2= 8*33.80/10.40
which is 270.4/10.40
26 is the number of oranges which can be bought with 33.80 rupees
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Answer 2

Cost of 8 oranges = ₹10.40
Cost of 1 orange = ₹10.40 / 8 = ₹1.3

n = ₹33.80 / (₹1.3 / orange) = 26 oranges

Total 26 oranges can be bought for ₹33.80