If 8 ships out of 10 ships arrive safely, find the probability that at least one would arrive safely out of 5 ships selected at random
If 8 ships out of 10 ships arrive safely, find the probability that at least one would arrive safely out of 5 ships selected at random
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This is a case of binomial distribution with p=31, n=5 and r=4.
Also, P(X=r)=nCrpr(1−p)n−r
We need to find P(X≥4)=P(X=4)+P(X+5)=5C4(31)4(32)+5C5(31)5(32)0=24311
i perfect don't now, excuse if any mistakes are there
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