Math, asked by barpan806, 1 month ago

if 8 sin^2 theta + 2 cos theta =5, 0°<theta<90° then the value of tan^2 theta+sec^2 theta+sin^2 theta will be

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Answered by chhirolyaanil7890

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if 8 sin^2 theta + 2 cos theta =5, 0°<theta<90° then the value of tan^2 theta+sec^2 theta+sin^2 theta will be

i)23/9ii)305/104 iii)431/144 iv) 153/73

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