Question

If 8 sin θ = 4 + cos θ, find sin θ​

Answer 1

Answer:

8sinx=4+cosx

or, 8sinx−4=cosx

Squaring both side

64sin

2

x−64sinx+16=cos

2

x

or, 64sin

2

x−64sinx+16−1+sin

2

x=0

or, 65sin

2

x−64sinx+15=0

or, 65sin

2

x−39sinx−25sinx+15=0

or, 13sinx(5sinx−3)−5(5sinx−3)=0

or, (13sinx−5)(5sinx−3)=0

either , 13sinx−5=0 OR 5sinx−3=0

or, 13sinx=5 OR 5sinx=3

∴

sinx=5/13

OR ∴

sinx=5/13

Answer 2

Answer:

Sorrt I don't understand