If 8 taps can fill a tank in 35 minutes, how much time will be taken to fill the tank if 3 taps go out of order? (It is given that the rate of flow of water is constant)
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If 8 taps can fill a tank in 35 minutes, how much time will be taken to fill the tank if 3 taps go out of order? (It is given that the rate of flow of water is constant)
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Answer:
Given that,
8 taps of the same size fill a tank in 27 minutes.
So, 1 tap can fill the tank in 8×27=216 minutes
If two taps go out of order, then the remaining taps =8−2=6
Therefore, Time taken by 6 taps to fill the tank =
6
216
=36 minutes.
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