If 8% (w/v) solution of glucose is isotonic with 2%(w/v) solution of a non-electrolyte solute A, then the molar mass of A is
Answers
Answer:
45
Explanation:
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Given info : If 8% (w/v) solution of glucose is isotonic with 2%(w/v) solution of a non-electrolyte solute A.
To find : The molar mass of A is..
solution : This question can be solved easily when you understand the meaning of isotonic solution.
isotonic solution : it denotes to a solution having same osmotic pressure as the other solution.
so here,
osmotic pressure of glucose solution = osmotic pressure of solution of non electrolyte solute A
⇒C₁RT = C₂RT
⇒C₁ = C₂
⇒concentration of glucose = concentration of solution of solute A
⇒ (8g/molar mass of glucose) × 1000/100 ml = (2g/molar mass of solute A) × 1000/100ml
⇒8/180 = 2/molar mass of A
⇒molar mass of A = 180/4 = 45 g/mol
Therefore the molar mass of solute A is 45 g/mol or amu.