Math, asked by ankithashettybs46, 1 month ago

If 8, x-1, 16 are A.P then find the value of x​

Answers

Answered by tejuvisha06
4

Answer:

a+c/2

a=8, c=16

8+16/2

24/2

x-1 is 12

therefore x = 13

Answered by pulakmath007
0

The value of x = 13

Given :

8 , x - 1 , 16 are in AP

To find :

The value of x

Concept :

If a , b , c are three consecutive terms of an AP then 2b = a + c

Solution :

Step 1 of 2 :

Form the equation to find the value of x

Here it is given that 8 , x - 1 , 16 are in AP

We know that if a , b , c are three consecutive terms of an AP then 2b = a + c

By the given condition

2(x - 1) = 8 + 16

Step 2 of 2 :

Find the value of x

2(x - 1) = 8 + 16

⇒ 2x - 2 = 24

⇒ 2x = 26

⇒ x = 26/2

⇒ x = 13

Hence the required solution is x = 13

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