Question

if 8^x+1=64 then the value of 3^2x+1

Answer 1

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We have to find the value of 3^2x+1 provided 8^(x + 1) = 64

So,

2³^(x + 1) = 64

2³^x+3 = 2^6

Equating the exponents we get —

3x + 3 = 6

3x = 6 - 3

3x = 3

x = 3 / 3

x = 1

By substitute in 3^2x+1 we get —

3^2×1+1

= 3^2+1

= 3³

= 27

The real value of 3^2x+1 is 27. (Answer).

Step-by-step explanation:

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