Question

If 8^(x+1) -8^(x-1) =126, then the value of x is wht?

Answer 1

hope it may help you .............

Answer 2

Answer:

Answer:

$x=\dfrac{4}{3}$

Step-by-step explanation:

Given: $8^{x+1}-8^{x-1}=126$

To solve for x

$8^{x+1}-8^{x-1}=126$

$8^{x}\cdot 8-\dfrac{8^{x}}{8}=126$

$\dfrac{64\cdot 8^{x}-8^x}{8}=126$

$63\cdot 8^x=8\times 126$

$8^x=16$

$2^{3x}=2^4$

$3x=4$

$x=\dfrac{4}{3}$

Hence, The value of x is $\dfrac{4}{3}$

Step-by-step explanation: