If 8^x × 5^(-y) = (0.05)^(-y) × (25)^(-3x/2), then the value of x: y will be?
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Answer:
Here,
f(x)=x
3
−6x
2
+9x+15=0
⇒f
′
(x)=3x
2
−12x+9.
For local maxima and minima we must have f
′
(x)=0
Now,
f
′
(x)=0 ⇒3(x
2
−4x+3)=0
⇒3(x−3)(x−1)=0⇒x=3orx=1.
Case. ! when x=3
In this case , when x is slightly less than 3 then f
′
(x)=3(x−3)9x−1) is negative and when x is slightly more than 3 then f
′
(x) is positive.
Thus, f
′
(x) changes from negative to positive as x increases through 3.
So, x=3 is a point of local minimum.
Case 2, when x=1
In this case, when x is slightly less than 1 then f
′
(x)=3(x−3)(x−1) is positive and when x is slightly more than 1 then f
′
(x) is negative.
Thus, f
′
(x) changes sign from positive to negative as x increases through 1.
So, x=1 is a point of local maximum.
Local maximum value =f(1)=19.
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