- If 8 years ago the ages of P and Q were in the ratio
2:3 and after 7 years the ratio of their ages will be 3:4
then what is the present age of P?
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Answer:
Answer is 22 years
Step-by-step explanation:
Let the age 8year ago of
p be =2a
and q be=3a
after seven year
p age will be 2a+7 after 7 year which is equal to 3b
2a+7=3b
b=(2a+7)/3
q age will be 3a+7 after 7 years which is equal to 4b
3a+7=4b
3a+7=4*(2a+7)/3
9a+21=8a+28
a=7
P age after 7 year =2a+7=2*7+7=21
as earlier we know age before 8 year and then we found age after 7 year so present age will be age after seven year +1 so answer is 21+1=22years
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