If 80 gm NaOH is mixed with 1000 gm water. Find the molality of this solution? (1) 3m
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Answered by
1
Answer:
Let x be the mass of solution.
Mass of NaOH=
100
x×20
Molar mass of NaOH=40g
∴ Number of moles= (
100
20x
)/40=
200
x
Now mass of solvent in the solution= x−
100
20x
=
100
80x
∴ Molality=
(80x/100)
x/200
×1000=6.25M
Answered by
0
Answer:
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