If 80 gm of NaOH is present in water to make 1 kg of solution . Then calculate Molality.
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molality= 10 molal
molality= no of moles of solute/weight of solvent in kg
no of moles= 80/40
=2
mass of solvent=mass of soln-mass of solute
=1kg-0.8kg
=0.2
m= 2/0.2
=10 molal
hope it helps u
molality= no of moles of solute/weight of solvent in kg
no of moles= 80/40
=2
mass of solvent=mass of soln-mass of solute
=1kg-0.8kg
=0.2
m= 2/0.2
=10 molal
hope it helps u
Sid10714:
Your answer is actually wrong correct answer is 2.17 ,you took 0.8 instead of 0.08
I'm really sorrt
sorry
answer is 2.17
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