Question

IF 80 gm of NaOH present in
one litre solution
then its
concentration is......
Normal
​

Answer 1

Answer:

2N is the answer.

Explanation:

Molarity = no.of moles / Volume of Solution

M = n/V

n = Given weight / Gram molecular weight

n = 80 / 40

n = 2 moles.

Volume = 1 liter.

Therefore, M = 2/1 =2 moles/liter.

Normality = Molarity * x-factor

x-factor can be:-

• Acidity for bases
• Basicity for acids
• ±charge for salts
• Change in oxidation number of oxidant or reductant.

In this case, NaOH is a base.

Acidity is the number of replaceable OH⁻ ions  present in one molecule of the base.

Acidity of NaOH is 1.

Therefore, Normality = 2 * 1

Normality = 2N.