Question

If 80 gram of water at 45⁰ C temperature is added to 20 gram of water at 30⁰C temperature. Then what will be the temperature of mixture?​

Answer 1

Answer:

75 is correct

Explanation:

45C + 30C =75C

80gram water +20 gram water =100 gram water

Ans. 100 gram water at 75C temperature.

Answer 2

Step by Step explanation:

Given: 80 grams water has $45$°C, and 20 grams water has $30$°C.

To find: The temperature of the mixture.

For calculation of the temperature of the mixture,

We know that 80 grams of water have $45$°C temperature (T1) and 20 grams of water has $30$°C temperature(T2),

Thus, the new temperature of mixture (NT),

⇒ $T1+T2=NT$

⇒$45$° $+ 30$°

⇒$75$°C.

Hence, the temperature of the mixture will be $75$°C.