if 80% of first order reaction completed in 20 minutes so find out the time required to complete it 95%
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2
answer= 40.04minutes
legandrytmr4457:
this is correct answer
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0
Answer:
If 80% of the reaction is completed in 20minutes then the portion left will be 100-80=20 hence 0.2part of the original concentration will be left.
If initial concentration is Ao then final concentration A will be 0.2Ao.
Hence, applying the formula to calculate K.
K=1/t * ln(Ao/A).
K= 1/20 *ln(10/2).
K=1/20*ln(5).
Now, to find the time when the reaction is 95% completed hence final concentration is A=0.05Ao.
K=1/t * ln(Ao/A).
K= 1/t *ln(100/5).
K=1/t*ln(20).
So, equating both the equations we get the value of t as.
t = 20*1.86 = 37.2minutes.
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