Question

If ₹8000 becomes ₹9261 at 5% p.a. compounded annually. Then find the time period.

Answer 1

Given :

A = Rs. 9261 .

P = Rs. 8000 .

R = 5%

To find :

N = ?

Solution :

$= > 9261 = 8000(1 + \frac{5}{100} ) {}^{n}$

$= > \frac{9261}{8000} = (1 + \frac{1}{20} ) {}^{n}$

$= > \frac{21 {}^{3} }{20 {}^{3} } = (\frac{21}{20}) {}^{n}$

$= > ( \frac{21}{20} ) {}^{3} = \frac{21}{20} {}^{n}$

$n = 3$

Hence , the time period n = 3.

☆Additional Information ☆

Percentage: a rate, number, or amount in each hundred.

Answer 2

Answer:

A = Rs. 9261 .

P = Rs. 8000 .

R = 5%

To find :

N = ?

Solution :

= > 9261 = 8000(1 + \frac{5}{100} ) {}^{n}=>9261=8000(1+

100

5

)

n

= > \frac{9261}{8000} = (1 + \frac{1}{20} ) {}^{n}=>

8000

9261

=(1+

20

1

)

n

= > \frac{21 {}^{3} }{20 {}^{3} } = (\frac{21}{20}) {}^{n}=>

20

3

21

3

=(

20

21

)

n

= > ( \frac{21}{20} ) {}^{3} = \frac{21}{20} {}^{n}=>(

20

21

)

3

=

20

21

n

n = 3n=3

Hence , the time period n = 3.

Step-by-step explanation:

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