Math, asked by sonalmadasamy2001, 3 months ago

If 81 students can do a painting on a wall of length 448m in 56 days. How many students can do the painting on a similar type of wall of length 160m in 27 days? 

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Answers

Answered by pushpa6855
1

Answer:

students × length×days= students × length×days

\begin{gathered}81 \times 448 \times 56 = students \times 160 \times 27 \\81 \times 448 \times 56 \div 160 \times 27 = students \\ students = 2032128 \div 4320 \\ students = 470.4\end{gathered}

81×448×56=students×160×27

81×448×56÷160×27=students

students=2032128÷4320

students=470.4

Answered by manojkumar147j
0

Answer:

students × length×days= students × length×days

\begin{gathered}81 \times 448 \times 56 = students \times 160 \times 27 \\81 \times 448 \times 56 \div 160 \times 27 = students \\ students = 2032128 \div 4320 \\ students = 470.4\end{gathered}

81×448×56=students×160×27

81×448×56÷160×27=students

students=2032128÷4320

students=470.4

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