if 81z2 is a multiple of 3. when z is a digit. what is the value of z
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the number is 81z2.
As it is a multiple of 3, it is divisible by 3.
So,
8+1+z+2 = 3k (k is constant)
11 + z = 3k
For z to be smallest 3k = 12,
11+z=12
z=1
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