Question

If (89)2 is added to the square of a number, the answer so obtained is 16202. What is the (1/26) of that number?

Answer 1

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Here is your answer.
Let the number is x
ATQ
$(89) {}^{2} + x {}^{2} = 16202 \\ 7921 + x {}^{2} = 16202 \\ x {}^{2} = 16202 - 7921 \\ x = \sqrt{8281} \\ x = 91 \\ \\ now \\ = \frac{1}{26} \times 91 \\ = 3.5$
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Answer 2

If (89)2 is added to the square of a number, the answer so obtained is 16202. What is the (1/26) of that number?

Solution:

Let the number be X.

=> (89)^2 + X^2 = 16202

=> X^2 = 8281

=> X = 91

=> 1/26 of 91 = 3.5

So, the (1/26) of that number is 3.5