Math, asked by anuprarthana6377, 1 year ago

if 8a - 64b - c = 24 cube root abc where a,b,c not equal to zero then









Answers

Answered by yashuu43
1
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Answered by Shaizakincsem
3

The question is incomplete here is the complete question:

If 8a - 64b- c = 24^3√abc, where a, b, c is not equal to 0, then which of the following can be true?

(1).2√a-4 3√b-3√c=0

 (2).2√a=4 3√b=3√6

 (3).a+b+c=0

(4).a=b=c

Answer:

The correct answer for this question is Option 1) 2∛a - 4∛b - c = 0

The 2nd option cannot be true because if you sort it out it is not equal to zero.

and 3 and 4 cannot be true because here a is 8 and b is 63.

If there is any confusion please leave a comment below.

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