if 8k + 4, 6 k - 2, 2 k + 12 are in AP then the value of k is answer is 10
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if k =10 , common difference = ? or d = ?,
a1= 8k + 4 , a2 = 6k - 2 , a3 = 2k + 12
8(10) + 4 , 6(10) - 2 , 2(10) + 12 are in AP
80 + 4 , 60 -2 , 20 + 12
84 , 58 , 32
using ,
d = a2 - a3 = a1 - a2,
d = 58 - 32 = 84 - 58
d = 26 = 26
therefore , d = 26,
yes, k =10 ,
Hence finded
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