Math, asked by ramubhagya9843, 11 months ago

if 8k +4, 6k-2 ,2k+12 are in a.p. then the value of K is​

Answers

Answered by Anonymous
10

Answer:

when these r in ap then,

8k+4 + 2k+12 = 2(6k -2)

= 10k +16 = 12k -4

= 16+4 = 12k-10k

= 20 = 2k

= k = 10

Answered by chmadhan
0

Answer:

K=3

Step-by-step explanation:

  1. Given that a1=8k+4 and a2=6k-2

FINDING

  1. d=a2-a1
  2. d=6k-2-(8k+4)
  3. d=6k-2-8k-4
  4. d=-2k-6
  5. -2k=-6
  6. k=6/2
  7. k=3
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