if 8k-4, 6k-2 and 2k-7 are three consecutive terms of an AP, find the value of k.
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Since terms are in AP, common difference i.e. d is same
d = second term - first term
= 6k -2 - ( 8k -4)
= -2k +2
d = third term - second term
= 2k-7 -(6k-2)
= -4k -5
So we get. -2k +2 = -4k -5
On solving we get , k = -7/2
d = second term - first term
= 6k -2 - ( 8k -4)
= -2k +2
d = third term - second term
= 2k-7 -(6k-2)
= -4k -5
So we get. -2k +2 = -4k -5
On solving we get , k = -7/2
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