Question

If 8sinA = 4 + cosA thdn find TanA

Answer 1

Given Equation is

8sinA = 4 + cosA

On dividing both side by cosA we have

8sinA/cosA = 4/cosA + cosA/cosA

8tanA = 4secA + 1

This can be written as

8tanA - 1 = 4secA

On squaring both side ,we get

[8tanA-1 ]^{2} = [4secA]^{2}

Using [a-b]^2 = a^2 + b^2 -2ab

[8tanA]^2 + 1 - 2.1.8tanA = 16sec^2A

64tan^(2)A + 1 - 16tanA = 16sec^(2)A

64tan^(2)A + 1 - 16tanA = 16[1 + tan(2)A]

64tan^(2)A + 1 - 16tanA = 16 + 16tan^(2)A

48tan^(2)A - 16tanA - 15 = 0

On solving this equation , we have

tanA = 0.45 and tanA = - 0.417

Answer 2

Answer:

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