Math, asked by chinmay5jan, 10 months ago

If 8u = 6u + 8, then u =_____? If 4a = –5a + 45, then a =_____ ? if 4q + 5 = 17, then q =_____? If –5t – 60 = – 70, then t = ______? If 3c = c +12, then c =_____? If 3 (k + 1) = 24, then k =_____? If (s ÷ 4) + 98 = 100, then s =________? If (5p ÷ 3) + 9 = 24, then p =_____?

Answers

Answered by sriza31
9

Answer:

8u=6u +8

8u-6u=8

2u=8

u=8/2

u=4

4a= -5a + 45

4a + 5a = 45

9a = 45

a = 45/9

a = 5

4q + 5 = 17

4q = 17-5

4q = 12

q = 12/4 =3

-5t - 60 = -70

-5t = -70 - 60

-5t = -130

t = -130/-5 = 26

3c = c + 12

3c-c = 12

2c = 12

c = 12/2 = 6

3(k+1)=2

3k + 3= 2

3k = 5

k = 5/3

s÷4 + 98 = 100

4/s + 48 = 100s

4 + 48 = 100s

52= 100s

s = 52/100

s = 13/ 25

5p ÷ 3 + 9 = 24

5p/3 + 9 = 24

5p + 9 = 24× 3

5p = 72 - 9

5p = 63

p = 63/ 5

Answered by pinjaraarifisha
11

Answer:

8u = 6u + 8,

8u-6u=8

=>2u=8

=>u=8/2

therefore u =4

4a = –5a + 45,

4a+5a=45

=>9a=45

then a =45/9

therefore,a=5

4q + 5 = 17

4q=17+5

=>4q=22

=>q=22/4

therefore q=5.5

–5t – 60 = – 70,

–5=–70+60

–5t=–10

=>t=–10/–5

therefore, t =2

3c = c +12,

3c–c=12

2c=12

=>c=12/2

therefore, c=6

3 (k + 1) = 24

3k+3=24

=>3k=27

=>k=27/3

therefore, k =9

(s ÷ 4) + 98 = 100,

 \frac{s}{4}  + 98 = 100 \\  \frac{s}{4}  = 198 \\  => s = 198 \times 4 \\ thus, \: s = 792

(5p ÷ 3) + 9 = 24

 \frac{5p}{3}  + 9 = 24 \\ \frac{5p}{3} =24  - 9 \\  \frac{5p}{3} = 15 \\ 5p = 15 \times 3 \\ 5p = 30 \\  =  > \: p =  \frac{30}{5}  \\ therefore, \: p = 6

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