Question

if 8x=7,15,2x-7 are the three consecutive terms of as find the value of x .write algebric sequence

Answer 1

Step-by-step explanation:

Given:if 8x+7,15,2x-7 are the three consecutive terms of A.P.

To find:find the value of x .write algebric sequence.

Solution:

As given terms are three consecutive terms of A.P., so to find the value of x.

Calculate the common difference and thus solve for the value of x

Common difference d:Second term-first term

$d = 15 - (8x + 7) \\ \\ d = 15 - 8x - 7 \\ \\ d = 8 - 8x \: \: ...eq1$

Also

Common difference d: Third term-Second term

$d = 2x - 7 - 15 \\ \\ d = 2x - 22 ...eq2$

Compare these two equations

$8 - 8x = 2x - 22 \\ \\ - 8x - 2x = - 22 - 8 \\ \\ - 10x = - 30 \\ \\ 10x = 30 \\ \\ x = 3$

Thus,

value of x is 3.

Algebraic sequence is

$8x + 7 \\ \\ = 8 \times 3 + 7 \\ \\ = 24 + 7 \\ \\ = 31 \\ \\ and \\ 2x - 7 \\ \\ = 2 \times 3 - 7 \\ \\ = 6 - 7 \\ \\ = - 1$

Thus,

The Algebraic sequence is

31,15,-1

Hope it helps you .

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