Question

if 8x=coseca and 8/x=cota find the value of 4(x^2-1/x^2)

Answer 1

Hey frnd ! Voila your answer!!

8x = cosec a

by squaring both sides , we get

(8x)^2 = cosec^2 a........1)

now , 8/x = cot a

again by squaring both sides we get ,

(8/x )^2 = cot^2 a ..........2)

subtract 2) from 1) :-)



(8x)^2 - (8/x )^2 = cosec^2 a - cot^2 a

8^2 ( x^2 - 1/x^2 ) = 1 ( by using identity, cosec^2 @ - cot^2 @ = 1)


x^2 - 1/x^2 = 1/64............3)

now , according to question we have to find the value of 4(x^2-1/x^2).......4)

so substitute 3) in 4)

4× 1/64

=1/16

I hope it helps!!!!

Answer 2

Answer:

I hope it May helps you

Explanation:

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