Math, asked by antarapingle6, 7 months ago

If 8x multiply by 4y= 32 and 81x÷27y=3; find the value of x and y​

Answers

Answered by ishaanmahaseth
1

Answer:

x =y=+1 or-1

Step-by-step explanation:

8x × 4y = 32

32xy=32

i.e xy =1--------1

81x÷27y=3

81x=81y

i.e x=y---------2

putting the value of x in eqn (1) we get,

As,xy =1

or,x×x=1

or,x^2 =1

x=+1 or -1

as,x=y,so y=+1 or-1

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