Question

if 8xy+12y+4x+6=31x, then find x and y.​

Answer 1

Let's solve for x.

8xy+12y+4x+6=31x

Step 1: Add -31x to both sides.

8xy+4x+12y+6+−31x=31x+−31x

8xy−27x+12y+6=0

Step 2: Add -12y to both sides.

8xy−27x+12y+6+−12y=0+−12y

8xy−27x+6=−12y

Step 3: Add -6 to both sides.

8xy−27x+6+−6=−12y+−6

8xy−27x=−12y−6

Step 4: Factor out variable x.

x(8y−27)=−12y−6

Step 5: Divide both sides by 8y-27.

x(8y−27)

8y−27

=

−12y−6

8y−27

x=

−12y−6

8y−27

Answer:

x=

−12y−6

8y−27

Answer 2

$\huge\pink{Answer}$

• Solve one of the equations for one of the variables.
• Substitute that equation into the other equation, and solve for x.
• Substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

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