Question

if (9/4)-⁴x(2/3)³= (p/q)¹¹, then find the value of (p/q)-²

solve pls take ur time thank you ​

Answer 1

$\\ = > \huge \frac{9}{4}$

so, your required answer to this question is

9/4

Step-by-step explanation:

hope it's helpful,,

:-)

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Answer 2

Answer:

$\frac{9}{4} \: \: ans.$

Step-by-step explanation:

,

${ (\frac{9}{4}) }^{ - 4} \times {( \frac{2}{3}) }^{3} = ( { \frac{p}{q} })^{ 11} \\ = > { (\frac{4}{9} )}^{4} \times {( \frac{2}{3}) }^{3} = ( { \frac{p}{q} })^{ 11}\\ = > { ({ (\frac{2}{3}) }^{2} )}^{4} \times {( \frac{2}{3}) }^{3} = ( { \frac{p}{q} })^{ 11} \\ = > ({ \frac{2}{3} )}^{4 \times 2} \times {( \frac{2}{3}) }^{3} = ( { \frac{p}{q} })^{ 11} \\ = > {( \frac{2}{3}) }^{8} \times {( \frac{2}{3}) }^{3} = ( { \frac{p}{q} })^{ 11} \\ = > { (\frac{2}{3} )}^{ 8+ 3} = ( { \frac{p}{q} })^{ 11} \\ = >{ (\frac{2}{3} )}^{ 11} = ( { \frac{p}{q} })^{ 11} \\ when \: exponents \: are \: same \: then \: base \: are \: also \: same. \\ so ,\: \: \: \frac{p}{q} = \frac{2}{3} \\ = > ( { \frac{p}{q}) }^{ - 2} \\ = > ( { \frac{2}{3} )}^{ - 2} \\ = > ( { \frac{3}{2} )}^{ 2} \\ = > \frac{9}{4} \: \: ans.$

Hope it's helpful to you :) :)