Question

If 9/5 of a number exceeds 5/7 of that number by 70, find that number.
​

Answer 1

Answer:

Let the number be x

So

9x/5-5x/7=70

63x-25x/35=70

38x/35=70

X=70*35/38

X=2660/38

X=1330/19( please follow me)

Answer 2

SOLUTION

Let the number be x

Then,

$\frac{9x}{5} = \frac{5x}{7} + 70 \\ \\ = > \frac{9x}{5} - \frac{5x}{7} = 70 \\ \\ = > \frac{63x - 25x}{35} = 70 \\ \\ = > 38x = 2450 \\ \\ = > x = \frac{2450}{38} = \frac{1225}{19} \\ \\ = > x = 64.47$

hope it helps ☺️