if 9/5 of a number exceeds 5/7 of that number by 70, find that number
Answers
Answered by
73
Let the number be x
So
9x/5-5x/7=70
63x-25x/35=70
38x/35=70
X=70*35/38
X=2660/38
X=1330/19
So
9x/5-5x/7=70
63x-25x/35=70
38x/35=70
X=70*35/38
X=2660/38
X=1330/19
shivam293mnb:
your answer is wrong
Answered by
102
here...is your answer....and hope it helps you
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