If (9,-7), (2, 4) and 2010) are the mich joints
of the sides AB, BC and CA respectively, then
find the
area of triangleABE
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Answer: The vertices are A(11,12), B(1,2) and C(5,6).
Step-by-step explanation:
As shown in the figure, let A(a,b), B(c,d) and C(e,f) be the vertices of ΔABC. Given that D(3,4), E(8,9) and F(6,7) are the mid-points of the sides BC, CA and AB respectively.
Since D is the mid-point of BC, so
Similarly, since F is the mid-point of AB, so
∴
Also, since E is the mid-point of AC, so
Solving the above linear equations, we get
Thus, the vertices of ΔABC are A(11,12), B(1,2) and C(5,6).
Apologies, if this is not what you wanted..
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