Question

If (9/7) 3 x (49/81) 2x-6 =(7/9) 9 , then the value of x is:

Answer 1

Step-by-step explanation:

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Answer 2

We can recall that:

$a^m\timesa^n=a^m^+^m\\\frac{a^m}{a^n}=a^m^-^n\\ a^m=\frac{1}{a^-^m} \\a^-^m=\frac{1}{a^m}$

$(\frac{a}{b})^-^x=(\frac{b}{a})^x$

Given,

$(\frac{9}{7})^3\times (\frac{49}{81})^2^x^-^6=(\frac{7}{9})^9\\(\frac{7}{9})^-^3\times[(\frac{7}{9})^2]^2^x^-^6=(\frac{7}{9})^9\\(\frac{7}{9})(-3+2x-6)=(\frac{7}{9})^9\\-9+2x=9\\2x=18\\x=9$