if 9.8 GM's , of H2SO4 is neutralised exactly with strong alkali , the heat evolved ( ∆H of neutralization is 13.6 K.cal
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Answer:
2.72 KCAL
Explanation:
H
2
SO
4
→2H
+
+SO
4
2−
9.8 gms =
98
9.8
=0.1 mole of H
2
SO
4
= 0.2 mole of H
+
ion in aqueous medium
ΔH of neutralization is 13.6 kcal.
The heat evolved =0.2×13.6=2.72 kcal
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