If 9 * 81^x = 1 / 27^x-2, find x
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9 * 9^2x = 3^-3(x - 2)
3^2 * 3^4x = 3^ - 3(x - 2)
3^(4x + 2) = 3^ -3 (x - 2)
4x + 2 = - 3x + 6
7x = 4
X = 4/7
3^2 * 3^4x = 3^ - 3(x - 2)
3^(4x + 2) = 3^ -3 (x - 2)
4x + 2 = - 3x + 6
7x = 4
X = 4/7
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