If 9 * 81^x = 1 / 27^x-3, find x
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9×81^x = 1/27^x-3
3²×3^4x = (1/3)^3(x-3)
3^2+4x = 3^-[3(x-3)]
Bases are equal. Exponents must be equal.
2+4x = -(3x-9)
2+4x = -3x+9
4x+3x = 9-2
7x = 7
x = 7/7
x = 1
Therefore, the value of x is 1
3²×3^4x = (1/3)^3(x-3)
3^2+4x = 3^-[3(x-3)]
Bases are equal. Exponents must be equal.
2+4x = -(3x-9)
2+4x = -3x+9
4x+3x = 9-2
7x = 7
x = 7/7
x = 1
Therefore, the value of x is 1
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