if 9,B&,7 are in ap then the value of B is
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9 , B and 7 are in AP so the common difference is also same
B-9 = 7 -B
2B =7+9
2B =16
B=8
Value of B is 8
B-9 = 7 -B
2B =7+9
2B =16
B=8
Value of B is 8
Answered by
0
Hey mate !!
Here's the answer !!
Given: 9, B, 7 are in AP
To Find: B
Proof:
In a AP, the difference of second term to the first term is equal to the difference of third term to that of second term.
That is,
a₂ - a₁ = a₃ - a₂
a₁ = 9
a₂ = B
a₃ = 7
= B - 9 = 7 - B
= B + B = 7 + 9
= 2B = 16
=> B = 16 / 2 = 8
Hence the value of B is 8
Hope my answer helped you !!
Cheers !!
Here's the answer !!
Given: 9, B, 7 are in AP
To Find: B
Proof:
In a AP, the difference of second term to the first term is equal to the difference of third term to that of second term.
That is,
a₂ - a₁ = a₃ - a₂
a₁ = 9
a₂ = B
a₃ = 7
= B - 9 = 7 - B
= B + B = 7 + 9
= 2B = 16
=> B = 16 / 2 = 8
Hence the value of B is 8
Hope my answer helped you !!
Cheers !!
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