Question

If 9 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 8 engines, each running 13hours a day, it being given that 3 engines of former type consume as much as 4 engines of latter type?

Answer 1

Answer:

"Let required amount of coal be x metric tonnes

More engines, more amount of coal (direct proportion)

If 3 engines of first type consume 1 unit, then 1 engine will consume 1/3 unit which is its the rate of consumption.

If 4 engines of second type consume 1 unit, then 1 engine will consume 1/4 unit which is its the rate of consumption

More rate of consumption, more amount of coal (direct proportion)

More amount of coal (direct proportion)

9×13×8×x=8×14×13×24⇒3×8×x=8×6×13⇒3×x=6×13⇒x=2×13=26

"

Step-by-step explanation:

Answer 2

Answer: 26

Step by step explanation:

Let required amount of coal be x metric tonnes.

This question is Direct promotional question. Because, More engines = More coal. According to question, 3 engines will consume 1 unit, So, 1 engine = 1/3 unit.

Now,

$\frac{1}{3}$ => is Rate of consumption

In second, 4 engines will consume 1 unit. Which is same to the 3 engines. Here also, 1 engine will consume the 1/4 unit. Here also, 1/4 is the total consumption.

=> 1/4 is the rate of consumption

More amount of coal:-

=> 9 × 13 × 8 × x

=> 8 × 14 × 13 × 24

=> 3 × 8 × x

=> 8 × 6 × 13

=> 3 × x = 6 × 13

=> 2 × 13

=> 26