Question

if 9 gram of Aluminium is heated with 16 gram of O2 then the maximum mass of Alumina Al to O3 formed is atomic weight of air is equal to 27

Answer 1

Answer:no of moles of aluminum=1/3

No of moles of oxygen = 1/2

Equation : 4Al + 3O2 => 2Al2O3

Explanation:

Compare the number of moles of aluminum and oxygen separately with product

For aluminium

4: 2 => 1:1/2 we have 1/3 moles of aluminium so × 1/3 on b.s of ratio we have 1/6 moles of product from aluminium

Now for oxygen we have 1/2 moles of oxygen

The same eq is used for this comparison of moles between oxygen and product

From equation : 3:2 => 1 : 3/2 we have 1/2 moles of oxygen present × b.s of ratio by 1/2 so we get 3/4 moles of product(alumina)

So we get max moles from oxygen which are 3/4

Multiply 3/4 by molar mass of alumina you will get the answer

Molar mass of alumina is = 102 g/mol

Answer 2

Answer:

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