Question

If 9% (i.e. q2) of an African population is born with a severe sickle cell anemia, what percentage of population (i.e. 2 pq) will be more resistant to malaria because they are heterozygous for sickle cell gene?
Options: (a) 0.3% (b) 0.7% (c) 42% (d) 210%

Answer 1

Answer:

I did not understand your question

Answer 2

Answer: (c) 42%

Explanation:

q2 = 9%

q = √9/100 = 3/10

q = 0.3

p + q = 1

p = 1 – q

= 1 – 0.3 = 0.7

2pq = 2 × 0.3 × 0.7

= 0.42

2pq = 42%

42% of individuals would be resistant to malaria.