if 9 liters out of 81 liters of a solution of salt and water is replaced by pure water to obtain a 48%
concentrated salt solution, then What was the initial concentration of the salt in the solution?
54%
55%
96%
Answers
Given : 9 liters out of 81 liters of a solution of salt and water is replaced by pure water to obtain a 48% concentrated salt solution,
To Find : What was the initial concentration of the salt in the solution?
Solution:
Solution = 81 Litre
Water = 9W litre
Salt = 81 - 9W
in 9 Litres
water = (9/81)9W = W
Salt = (9/81)(81 - 9W) = 9 - W
replaced by pure water
Water = 9W - W + 9 = 8W + 9
Salt = 81 - 9W - (9 - W) = 72 - 8W
48% concentrated salt solution, => 100 x (72 - 8W)/81 = 48
=> 100 x 8 ( 9 - W) = 81 x 48
=> 100 x 8 ( 9 - W) = 81 x 48
=> 9 - W = 4.86
=> W = 4.14
Salt = 81 - 9W = 81 - 9*(4.14) = 43.74
Salt % = (43.74/81) * 100
= 54 %
initial concentration of the salt in the solution = 54 %
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