Question

if 9^n+1 × (3^-n/2)^-2 - 27^n/3^m ×2^3 = 1/729 then prove that m-n = 2 ​

Answer 1

Answer:

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Answer 2

Answer:

9n+1*(3-n/2)-2-27n/(3m*2)3 = 1/729

32n+2 * 3n - 33n/33m*8 = 3-6

33n+2-33n/33m*8=3-6

33n(32-1)/33m*8 = 3-6      {take 3n outside}

33n/33m = 3-6

33n-3m = 3-6

33(n-m)= 3-6

3(n-m) = -6

n-m = -2

Given m+n = 5

sub the value of m = 5-n

so m = 3/2

n=7/2