Question

if 9^n ×3^2×(3^n/2)^-2-(27)^n=1/27 then prove that m-n =1​

Answer 1

Answer and Step-by-step explanation:( your questions incomplete so i wrote it again in my answer)

9ⁿ×3²×(3ⁿ÷²)⁻² - 27ⁿ / 3³^m×2³ =1/27

3²ⁿ×3²×3ⁿ - 27ⁿ / 3³^m × 2³ = 1/27

3³ⁿ+²-3³ⁿ / 3³^m × 2³= 1/3³

3³ⁿ(9-1) / 3³^m(8)= 3⁻³

3³ⁿ⁻³^m=3⁻³

3n-3m = -3

3(n-m)=-3

n-m = -1

m-n = 1

HOPE IT HELPS!!!!

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